4P+5O2--->2P2O5(1)
a) n P=6,2/31=0,2(mol)
Theo pthh
n O2=5/4n P=0,25(mol)
VO2=0,25.22,4=5,6(l)
b) P2O5+3H2O--->2H3PO4(2)
Theo pthh1
n P2O5=1/2 n P=0,1(mol)
Theo pthh2
n H3PO4=2n P2O5=0,2(mol)
m H3PO4=98.0,2=19,6(g)
C% H3PO4=\(\frac{19,6}{250}.100\%=7.84\%\)
\(\text{4P + 5O2}\rightarrow\text{2P2O5}\)
\(\text{a) nP=0,2 (mol)}\)
\(\Rightarrow nO2=\frac{5}{4}nP=0,25\left(mol\right)\)
\(\rightarrow\text{VO2=0,25.22,4=5,6 (l)}\)
\(\Rightarrow nP2O5=\frac{1}{2}nP=0,1\left(mol\right)\)
\(\rightarrow\text{mP2O5=0,1.142=14,2 (g)}\)
\(\text{b) P2O5 + 3H2O}\rightarrow\text{2H3PO4}\)
nH3PO4=2.nP2O5=0,2 (mol)
\(\rightarrow\)mH3PO4=0,2.98=19,6 (g)
\(\rightarrow\text{C%H3PO4=}\frac{19,6}{250}.100\%=\text{7,84 %}\)
