\(\dfrac{5}{x}-\dfrac{y}{3}=\dfrac{1}{6}\)
\(\Leftrightarrow\dfrac{5}{x}=\dfrac{2y+1}{6}\)
\(\Leftrightarrow x\left(2y+1\right)=30\)
x | 5 | -5 | 1 | -1 | 30 | -30 | 6 | -6 |
2y+1 | 6 | -6 | 30 | -30 | 1 | -1 | 5 | -5 |
x | 5 | -5 | 1 | -1 | 30 | -30 | 6 | -6 |
y | / | / | / | / | 0 | -1 | 2 | -3 |
Vậy \(\left(x;y\right)\in\left\{\left(30;0\right),\left(-30;-1\right),\left(6;2\right),\left(-6;-3\right)\right\}\)