Question

a) ( x + y )² - 2 ( x + y ) + 1
b) 4x² - 4x + 1 - y² - 8x - 16

Answer 1

\(\left(x+y\right)^2-2\left(x+y\right)+1=\left(x+y-1\right)^2\)

\(4x^2-4x+1-\left(y^2+8y+16\right)=\left(2x-1\right)^2-\left(y+4\right)^2\)

\(=\left(2x-1-y-4\right)\left(2x-1+y+4\right)=\left(2x-y-5\right)\left(2x+y+3\right)\)