\(a,=\sqrt{37-2.2\sqrt{3}.5}-\sqrt{37+2.2\sqrt{3}.5}\\ =\sqrt{\left(2\sqrt{3}-5\right)^2}-\sqrt{\left(2\sqrt{3}+5\right)^2}\\ =\left|2\sqrt{3}-5\right|-\left|2\sqrt{3}+5\right|\\ =2\sqrt{3}-5-2\sqrt{3}-5\\ =-10\)
\(b,đkx\ge\dfrac{1}{6}\\ \sqrt{3x+\sqrt{6x-1}}=\sqrt{2}\\ \left(\sqrt{3x+\sqrt{6x-1}}\right)=\left(\sqrt{2}\right)^2\\ 3x+\sqrt{6x-1}=2\\ \left(\sqrt{6x-1}\right)^2=\left(2-3x\right)^2\\ 6x-1=4-12x+9x^2\\ 9x^2-12x-6x+4+1=0\\ 9x^2-18x+5=0\\ 9x^2-3x-15x+5=0\\ 3x\left(3x-1\right)-5\left(3x-1\right)=0\\ \left(3x-5\right)\left(3x-1\right)=0\\ \left[{}\begin{matrix}3x-5=0\\3x-1=0\end{matrix}\right.=>x=\dfrac{5}{3}\left(thoaman\right);x=\dfrac{1}{3}\left(thoaman\right)\)
\(@Dosea\)
Cho mình sửa câu a nhé :
\(a,=\sqrt{\left(2\sqrt{3}-5\right)^2}-\sqrt{\left(2\sqrt{3}+5\right)^2}\\ =\left|2\sqrt{3}-5\right|-\left|2\sqrt{3}+5\right|\\ =5-2\sqrt{3}-2\sqrt{3}-5\\ =-4\sqrt{3}\)
\(@Dosea\)
