Gọi \(Cx\) // \(AB.\)
=> \(\widehat{A}=\widehat{C_1}\) (vì 2 góc so le trong)
Mà \(\widehat{A}=50^0\left(gt\right)\)
=> \(\widehat{C_1}=50^0.\)
Vì \(AB\) // \(EF\left(gt\right)\)
\(AB\) // \(Cx\)
=> \(Cx\) // \(EF.\)
=> \(\widehat{C_2}=\widehat{E}\) (vì 2 góc so le trong)
Mà \(\widehat{E}=70^0\left(gt\right)\)
=> \(\widehat{C_2}=70^0.\)
Ta có: \(\widehat{ACE}=\widehat{C_1}+\widehat{C_2}\)
=> \(\widehat{ACE}=50^0+70^0\)
=> \(\widehat{ACE}=120^0\)
Vậy \(\widehat{ACE}=120^0.\)
Chúc bạn học tốt!
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