\(\left(\dfrac{7}{8}\right)^5\cdot\left(\dfrac{21}{16}\right)^5=\left(\dfrac{7}{8}\cdot\dfrac{21}{16}\right)^5=\left(\dfrac{147}{128}\right)^5\)
tính
1, 125^5:25^7
2, 27^8:9^9
3,36^5:6^8
4, 49^6:7^10
5, 7^20:49^9
6, 1/2^10:1/8^3
7, (-1/2)^21:1/4^10
8,1/16^5:(-1/2)^18
9,1/5^30:1/25^14
10, 1/125^6:1/25^14
so sánh
63^7 và 16^12
b, 17^14 vaf 31^11
c, 2^67 và 5^21
d, 10^31 và 2^100
chứng tỏ: 8^7 - 2^18 chia hết cho 14. b) 5^14 . 5^15 . 5^16 chia hết cho 31 c) 81^7 - 9^13 +12^25 + 27^9 - 12^24 chia hết cho 11. Làm giúp mình nha mình cần gấp, ai làm nhanh tick
Đọc thêm Toán lớp 7
a,\(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
b,\(\left[\frac{5}{7}-\frac{7}{5}\right]-\left[\frac{1}{2}-\left(\frac{-2}{7}-\frac{1}{10}\right)\right]\)
c,\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{71}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{8}\)
d,\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
e,\(\left(\frac{1}{2}-\frac{13}{14}\right):\frac{5}{7}-\left(\frac{-2}{21}+\frac{1}{7}\right):\frac{5}{7}\)
g,\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)
1 Tínha \(\left(\dfrac{5.5^3}{5^2.49}\right)^{15}:\left(\dfrac{5^6}{434}\right)^7\)
b \(\dfrac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
làm nhanh giúp mik nha, chiều mai phải nộp rồi...thanks bn giúp mik nhiều lắm lun !!!
Bài 1: Tính giá trị biểu thức:
a, \(\frac{5^5.20^3-5^4.20^3+5^7.4^5}{\left(20+5\right)^3.4^5}\)
b, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
c, \(\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
chứng tỏ: 8^7 - 2^18 chia hết cho 14.
b) 5^14 . 5^15 . 5^16 chia hết cho 31
c) 81^7 - 9^13 +12^25 + 27^9 - 12^24 chia hết cho 11.
Làm giúp mình nha mình cần gấp, ai làm nhanh tick cho
cám ơn trước
thuc hien phep tinh
\(\dfrac{4^3+2^5+8^5}{8^3\times3+16+3^3}\)
Tính:
a) S=1.2+2.3+3.4+...+99.100
b) B=\(\dfrac{49^{24}.125^{17}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
c) C=\(\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}\right).3^5+\left(\dfrac{1}{3^5}+\dfrac{1}{3^6}+\dfrac{1}{3^7}+\dfrac{1}{3^8}\right).3^9+...+\left(\dfrac{1}{3^{97}}+\dfrac{1}{3^{98}}+\dfrac{1}{3^{99}}+\dfrac{1}{3^{100}}\right).3^{101}\)
d) D= \(3-3^2+3^3-3^4+...+3^{2017}-3^{2018}\)
