\(\dfrac{5}{3x+2}=2x-1\)
\(\Leftrightarrow\dfrac{5}{3x+2}=\dfrac{\left(3x+2\right)\left(2x-1\right)}{3x+2}\)
\(\Leftrightarrow5=\left(3x+2\right)\left(2x-1\right)\)
\(\Leftrightarrow5=6x^2-3x+4x-2\)
\(\Leftrightarrow5=6x^2+x-2\)
\(\Leftrightarrow6x^2+x=7\)
\(\Leftrightarrow x=1\)
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