\(4x\left(x-2018\right)-x+2018=0\)
\(\Rightarrow4x\left(x-2018\right)-\left(x-2018\right)=0\)
\(\Rightarrow\left(x-2018\right)\left(4x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2018=0\\4x-1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2018\\x=\dfrac{1}{4}\end{matrix}\right.\)
Vậy ..................................................
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