Question

\(4.\left(-1\right)-1-8+\left(-1\right).\dfrac{1}{2}+6+2+2.\left(-1\right)^2.\dfrac{1}{2}+2\)

Answer 1

\(4.\left(-1\right)-1-8+\left(-1\right).\dfrac{1}{2}+6+2+2.\left(-1\right)^2.\dfrac{1}{2}+2\)

\(=\left(4+\dfrac{1}{2}-2\right).\left(-1\right)+\left(-1-8+6+2+2\right)\)

\(=\dfrac{5}{2}.\left(-1\right)+1=\dfrac{-5}{2}+1=-\dfrac{3}{2}\)

Chúc bn học tốt

Answer 2

=(-4-1-8)+(-1/2)+(6+2+1+2)

=-13-1/2+11

=-2-1/2

=-3/2