Question

\(3^{x-1}+5x3^{x-1}=162\)

Answer 1

\(3^{x-1}+5.3^{x-1}=162\)

\(\Leftrightarrow6.3^{x-1}=162\)

\(\Leftrightarrow3^{x-1}=27\)

\(\Leftrightarrow3^{x-1}=3^3\)

\(\Leftrightarrow x-1=3\)

\(\Leftrightarrow x=3+1\)

\(\Leftrightarrow x=4\)

Answer 2

3^x-1 + 5 \(\times\) 3^x-1 = 162

=> 3^x-1 . (1 + 5) = 162

=> 3^x-1 . 6 = 162

=> 3^x-1 = 162 : 6 

=> 3^x-1 = 27

=> 3^x-1 = 37 = 3³

<=> x - 1 = 3

<=> x = 4.

Answer 3

\(3^{x-1}+5x3^{x-1}=162\)

\(3^{x-1}.1+5x3^{x-1}=162\)

      \(3^{x-1}.\left(1+5\right)=162\)

                \(3^{x-1}.6=162\)

                   \(3^{x-1}=162:6\)

                   \(3^{x-1}=27\)

                   \(3^{x-1}=3^3\)

\(\Rightarrow x-1=3\)

    \(x=4\)

Vậy \(x=4\)

 

Answer 4

3^x-1 + 5  3^x-1 = 162

<=> 3^x-1 . (1 + 5) = 162

<=> 3^x-1 . 6 = 162

<=> 3^x-1 = 162 : 6 

<=> 3^x-1 = 27

<=> 3^x-1 = 37 = 3³

<=> x - 1 = 3

<=> x = 4.