Question

cho hai đa thức M(x)=-5x³+3x⁴+7-9x

N(x)=-2x⁴+3x-5x³-7

tính M(x)=N(x)

Answer 1

\(M\left(x\right)+N\left(x\right)=-5x^3+3x^4+7-9x-2x^4+3x-5x^3-7\)

\(M\left(x\right)+N\left(x\right)=x^4-10x^3-12x\)

Answer 2

phép + hay - vậy bạn ?

Answer 3

bl giúp với toan j đou

 

Answer 4

Answer 5

Answer 6

\(M\left(x\right)+N\left(x\right)=\left(-5x^3+3x^4+7-9x\right)+\left(-2x^4+3x-5x^3-7\right)\)

\(M\left(x\right)+N\left(x\right)=-5x^3+3x^4+7-9x+-2x^4+3x-5x^3-7\)

\(M\left(x\right)+N\left(x\right)=\left(-5x^3-5x^3\right)+\left(3x^4-2x^4\right)+\left(7-7\right)+\left(-9x+3x\right)\)

\(M\left(x\right)+N\left(x\right)=-10x^3+x^4-6x\)