\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(36x^2-12x-36x^2+27x=30\)
\(15x=30\)
\(x=2\)
Giải:
\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)
\(\Leftrightarrow-12x+27x=30\)
\(\Leftrightarrow15x=30\)
\(\Leftrightarrow x=\dfrac{30}{15}\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\).
Chúc bạn học tốt!!!
3x (12x-4) -9x( 4x-3) = 30
3x.12x- 3x.4 -9x.4x+ 9x.3= 30
36x\(^2\)-12x-36x\(^2\) +18x =30
6x = 30
=> x= 5
Chúc bạn học tốt !!
3x(12x-4) – 9x(4x-3) = 30
=> 3x.12x – 3x.4 – 9x.4x +9x.(-3) = 30
=> 36x2 – 12x -36x2 + 27x = 30
=> -12x + 27x = 30
=> 15x = 30
=> x = 30 : 15
=> x = 2
