Câu a : \(\left(3x+1\right)\left(4x-2\right)-12x\left(x-3\right)=5\)
\(\Leftrightarrow12x^2-2x-2-12x^2+36x-5=0\)
\(\Leftrightarrow34x-7=0\)
\(\Leftrightarrow x=\dfrac{7}{34}\)
Vậy \(x=\dfrac{7}{34}\)
Câu b : \(\left(2x+1\right)\left(4x-2\right)-\left(8x+2\right)\left(x+5\right)=4\)
\(\Leftrightarrow8x^2-2-8x^2-42x-10-4=0\)
\(\Leftrightarrow-42x-16=0\)
\(\Leftrightarrow x=-\dfrac{16}{42}=-\dfrac{8}{21}\)
Vậy \(x=-\dfrac{8}{21}\)
Chúc bạn học tốt !
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