Tuyển Cộng tác viên Hoc24 nhiệm kì 30 tại đây: https://forms.gle/T8wg79khMGHeXQuDA
a) \(\dfrac{790^4}{79^4}\)
b) \(\dfrac{3^2}{0,375^2}\)
c) \(3^2.\dfrac{1}{243}.81^2.\dfrac{1}{3^3}\)
d)\(\left(4.2^5\right):\left(2^3.\dfrac{1}{16}\right)\)
các bn giup mk vs nha
3) tìm x:
a) \(x^2=\dfrac{1}{16}\)
b)\(x^5\div x^2=\dfrac{-1}{64}\)
c)\(x^3\div x^2=\dfrac{32}{243}\)
d)\(\left(x^2\right)^2=\dfrac{81}{16}\)
(x-2/3)^3=1/27
(X+0,7)^3=-27
(2/3x-1/3)^5=1/243
tìm x thuộc Q bt:
a)\(\left(x-\dfrac{1}{2}\right)^2=0\)
b) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)
c) \(\left(2.x-3\right)^3=-8\)
d) \(\left(3.x-2\right)^5=-243\)
e) \(\left(7.x+2\right)^{-1}=3^{-2}\)
f) \(\left(x-1\right)^3=-125\)
g) \(\left(2x-1\right)^4=81\)
h) \(\left(2.x-1\right)^6=\left(2.x-1\right)^8\)
các bn ai bt lm lm ơn lm phước giải ra hộ mk vs mk sẽ tik mừ .... các bn giúp mk vs nhé huhu
Nhờ mọi người giúp mình vs!
Tìm x thuộc Q khi:
a)3x-1 =243
b)\(\left(\dfrac{2}{3}\right)^{x+1}=\dfrac{8}{4}\)
c) 3x+3x+2=270
d) \(\left(x-\dfrac{5}{2}\right)^2=144\)
e) \(\left(2x+1\right)^3=\dfrac{215}{27}\)
f) (2x-1)5 = -243
h) (27-1)2 = (2x-1)2
i) (2x+1)2 + (x+1)10 = 0
k) \(\dfrac{x-2}{5}=\dfrac{X+3}{2}\)
l) \(\dfrac{2}{x}=\dfrac{x}{50}\)
m) \(\dfrac{\left(x-3\right)}{4}=\dfrac{4}{x+3}\)
n) \(|x+\dfrac{3}{5}|-|x-\dfrac{7}{3}|\)
(x-1,2)^2=4
(x+1)^3=-125
(x+1,5)^8+(2,7-y)^10=0
3^-1.4^x+ 3.$^x+5/3. 27
9^-x. 27^x= 243
Bài 1:Tính giá trị biểu thức
\(_{1,}\)\(3^2.\dfrac{1}{243}.81^2.\dfrac{1}{3^3}\)
\(_{2,}\)(\(4.2^5\)):\(\left(2^3.\dfrac{1}{16}\right)\)
\(_{3,}\)\(\left(2^{-1}+3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)
\(_{4,}\)\(\left(-\dfrac{1}{3}\right)^{-1}-\left(-\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)
\(_{5,}\)[(0,1)\(^2\)]\(^0\)+[(\(\dfrac{1}{7}\))\(^{-1}\)]\(^2\).\(\dfrac{1}{49}.\left[\left(2^2\right)^3:2^5\right]\)
Bài 2:Rút gọn biểu thức
a,\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b,\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
c,\(\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3\)
\(\overline{2^7.5^2+512}\)
d,\(\left(\dfrac{2}{3}\right)^3.\left(-\dfrac{3}{4}\right)^2.\left(-1\right)^5\)
\(\overline{\left(\dfrac{2}{5}\right)^2}.\left(-\dfrac{5}{12}\right)^3\)
Tìm x
\(1.\left(x+0,7\right)^3=-27\)
\(2.\left(2x-1\right)^{10}=49^5\)
\(3.\left(\frac{2}{3}x-\frac{1}{3}\right)^5=\frac{1}{243}\)
\(4.\left(\frac{2}{5}-3x\right)^2=\frac{9}{25}\)
CÁC BẠN GIÚP MÌNH VỚI !!!!!