a: \(\widehat{xOt}=180^0-60^0=120^0\)
b: \(\widehat{mOt}=\widehat{mOy}=\dfrac{60^0}{2}=30^0\)
\(\widehat{nOt}=\widehat{nOx}=\dfrac{120^0}{2}=60^0\)
Do đó: \(\widehat{mOt};\widehat{nOt}\) là hai góc kề phụ
\(\widehat{mOy};\widehat{xOn}\) là hai góc kề nhau