2x(x-3)+5(x-3)=0
=>(2x+5)(x-3)=0
=>2x+5=0 hoặc x-3=0
=>x=-5/2 hoặc x=3
\(2x\left(x-3\right)+5\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(2x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-3=0\\2x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=\frac{-5}{2}\end{matrix}\right.\)
2x(x - 3) + 5(x - 3) = 0
=> ( 2x + 5) .(x - 3) = 0
=> 2x +5 = 0 hoặc x - 3 = 0
2x = -5 x = 0 + 3
x = -5 : 2 x =3
x = \(\frac{-5}{2}\)
Vậy x = \(\frac{-5}{2}\) hoặc x = 3