\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Rightarrow2x\text{ hoặc }x-\dfrac{1}{7}=0\)
+ Nếu 2x = 0 thì x = 0
+ Nếu x - \(\dfrac{1}{7}\) = 0 thì x = \(\dfrac{1}{7}\)
Vậy...
\(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=\dfrac{1}{7}\)
=>2x=0 hoặc x-\(\dfrac{1}{7}\)=0
=>x=0:2 hoặc x=0+\(\dfrac{1}{7}\)
=>x=0 hoặc x=\(\dfrac{1}{7}\)