Question

(2*x+3)^3=-8/27

 

 

 

Answer 1

Ta có: (2x+3)³=\(\frac{-8}{27}\)

=>(2x+3)³=(\(\frac{-2}{3}\))³

=>2x+3=\(\frac{-2}{3}\)

=>2x=\(\frac{-2}{3}+3\)

=>2x=\(\frac{7}{3}\)

=> x=\(\frac{7}{6}\)

Vậy x=\(\frac{7}{6}\)

Answer 2

\(\left(2x+3\right)^3=-\frac{8}{27}\)

\(\Rightarrow\left(2x+3\right)^3=\left(-\frac{2}{3}\right)^3\)

\(\Rightarrow2x+3=-\frac{2}{3}\)

\(\Rightarrow2x=-\frac{2}{3}-3\)

\(\Rightarrow2x=-\frac{11}{3}\)

\(\Rightarrow x=-\frac{11}{3}:2\)

\(\Rightarrow x=-\frac{11}{6}\)

Vậy : \(x=-\frac{11}{6}\)