\(\left(x-\dfrac{1}{3}\right)^3=-\dfrac{8}{27}\)
=>\(\left(x-\dfrac{1}{3}\right)^3=\left(-\dfrac{2}{3}\right)^3\)
=>\(x-\dfrac{1}{3}=-\dfrac{2}{3}\)
=>\(x=-\dfrac{2}{3}+\dfrac{1}{3}=-\dfrac{1}{3}\)
1/9 x 27 mũ x = 3 mũ x
giúp mình với
Cho 3 đa thức:
M(x)=3x mũ 3+ x mũ 2+ 4x mũ 4- x- 3x mũ 3+5x mũ 4 +x mũ 2 - 6; N(x)=-x mũ 2-x mũ 4+ 4x mũ 3- x mũ 2-5x mũ 3 + 3x + 1 +x; P(x)= 1 + 2x mũ 5 - 3x mũ 2 + x mũ 5 + 3x mũ 3 - x mũ 4- 2x
Giup mình nhanh nha!!!
1/3 mũ 2 x 3 mũ 4 x 3 mũ n = 3 mũ 7
giúp mình với
Tìm x biết
a) 3(1-4x).(x-1)+4(3x-2).(x+3)=-27
b) (x+3).(x2-3+9)-.(x-1).(x+1)=27
c) 2x2+3(x-1).(x+1)=5x.(x+1)
d) 8(x-1).(x+5)-(x+2).(x+5)=3(x-1).(x+2)
Tìm x biết: (x - 1/3)2 = -8/27
Giúp mk nha!
Bài 1:
a)\(\left|x-2\right|\)+\(\left|1-\dfrac{x}{2}\right|\)=0 b)\(\left(x-\dfrac{1}{3}\right)^3\)=\(\dfrac{-8}{27}\)
c)\(\dfrac{x^2}{6}\)=\(\dfrac{24}{25}\) c)\(\dfrac{x-1}{x+5}\)=\(\dfrac{6}{7}\)
Giúp mik làm bài này với ạ mik đang cần gấp tối nay mik phải nộp rồi mong mn giúp đỡ mik. Mik cảm ơn mn
Tìm x
1) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\) 2) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\) 3) \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
4) \(\left(\dfrac{4}{9}\right)^x=\left(\dfrac{8}{27}\right)^{10}\) 5) \(2^x=4^5.4^3\) help me !!!!
\(3^x=\frac{6}{1}.\frac{9}{2}.\frac{12}{3}...\frac{27}{8}\)
Câu 1. 1- (x + \(\dfrac{1}{3}\) )\(^2\) = \(\dfrac{5}{9}\)
Câu 2. 15 :( \(\dfrac{4}{9}\))\(^2\) . (\(\dfrac{8}{27}\))\(^2\) : (\(\dfrac{2}{3}\))\(^9\)
