Question

(2x^2+1)*(4X-3)=(2X^2+1)(x-12)

Answer 1

\(\Leftrightarrow\left(2x^2+1\right)\left(4x-3\right)-\left(2x^2+1\right)\left(x-12\right)=0\)

\(\Leftrightarrow\left(2x^2+1\right)\left(4x-3-x+12\right)=0\)

\(\Leftrightarrow\left(2x^2+1\right)\left(3x+9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x^2+1=0\\3x+9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x^2=-1\\3x=-9\end{matrix}\right.\Leftrightarrow}x=-3}\)

Answer 2

Đề: \(\left(2x^2+1\right).\left(4x-3\right)=\left(2x^2+1\right).\left(x-12\right)\) (1)

\(\left(1\right)\Leftrightarrow\left(2x^2+1\right)\left(4x-3\right)-\left(2x^2+1\right)\left(x-12\right)=0\\ \Leftrightarrow\left(2x^2+1\right)\left(3x+9\right)=0\Rightarrow\left[{}\begin{matrix}3x+9=0\\2x^2+1=0\left(VN\right)\end{matrix}\right.\Rightarrow x=-3\)