2(x-1)2+(x+3)2=3(x-2)(x+1)
2(x2 -2x+1)+(x2+6x+9)=3(x-2)(x+1)
2x2-4x+2+x2+6x+9=(3x-6)(x+1)
3x2+2x+11=3x2+3x-6x-6
3x2+2x+11=3x2-3x-6
3x2-3x2+2x+3x=11-6
5x=5
x=1
Ta có :
2(x - 1)2+(x + 3)2 = 3(x - 2)(x + 1)
<=> 2(x2 - 2x + 1) + (x2 + 6x + 9) = (3x - 6)(x + 1)
<=> 3x2 + 2x + 11 = 3x2 - 3x - 6
<=> 5x = 5
<=> x = 1.
Vậy x= 1.