\(\frac{2^5.9^3}{3^4.2^7}=\frac{\left(3^2\right)^3}{3^4.2^2}=\frac{3^6}{3^4.2^2}=\frac{3^2}{2^2}=\frac{9}{4}\)
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Đại số lớp 7
Các câu hỏi tương tự
Tìm x
\(a,3^{-2}.3^4.3^x=3^7\)
b,\(2^{-1}.2^x+4.2^x=9.2^5\)
Tìm số nguyên n
a, 3-2.34.33.3n=37
b,2-1.2n+4.2n=9.25
c, 2.16_>2n>4
Tìm số nguyên n
a, 3-2. 34. 3n = 37
b, 2-1. 2n+ 4.2n= 9.25
c, 2. 16 >_ 2n>4
Rút gọn :
A = \(\frac{2.8^4.27^8+4.6^9}{2^7.6^7+2^7.40.9^4}\)
B = \(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
Tìm n thuộc Z sao cho:
a)1/9.3^4.3^n=3^7
b)1/2.2^n+4.2^n=9.2^5
Tính nhanh : \(\frac{4^5.9^3-12^5}{2^{10}.8^1-2^9.9^2}\)
\(\dfrac{9^4.2^{15}}{2^6.24^3}\)
\(\dfrac{9^4.2^{15}}{2^6.24^3}\)