\(\dfrac{9^4.2^{15}}{2^6.24^3}=\dfrac{3^8.2^{15}}{2^6.3^3.2^9}=3^5\)
\(\dfrac{9^4.2^{15}}{2^6.24^3}=\dfrac{3^8.2^{15}}{2^6.3^3.2^9}=3^5\)
\(\dfrac{9^4.2^{15}}{2^6.24^3}\)
Câu 1. 1- (x + \(\dfrac{1}{3}\) )\(^2\) = \(\dfrac{5}{9}\)
Câu 2. 15 :( \(\dfrac{4}{9}\))\(^2\) . (\(\dfrac{8}{27}\))\(^2\) : (\(\dfrac{2}{3}\))\(^9\)
Thực hiện phép tính hợp lí (nếu có thể):
A = \(\dfrac{11}{9}.\dfrac{-3}{2}-\dfrac{11}{9}.\dfrac{15}{2}+\left(-2021\right)^0\)
Bài 1 tính .
a) \(\dfrac{\left(-3\right)^{10}.15^5}{25^3.\left(-9\right)^7}\)
b) 2\(^3\) +3 . (\(\dfrac{1}{9}\))\(^0\) -2\(^{-2}\) . 4 +[ (-2)\(^2\) : \(\dfrac{1}{2}\) ] . 8
Giúp mình với mình cảm ơn
1)\(\dfrac{27^4.4^3}{9^5.8^2}\)
2)\(\dfrac{8^5.3^{15}}{2^{14}.81^4}\)
Bài 1:
1/\(\left(-\dfrac{25}{13}\right)+\left(-\dfrac{19}{17}\right)+\dfrac{12}{13}+\left(-\dfrac{25}{17}\right)\) 6/ \(2\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}:\left(-\dfrac{3}{17}\right)\)
2/\(\dfrac{1}{2}-\left(-\dfrac{1}{3}\right)+\dfrac{1}{23}+\dfrac{1}{6}\) 7/\(\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
3/\(\left(-\dfrac{3}{7}\right).\dfrac{5}{11}+\left(-\dfrac{5}{14}\right).\dfrac{5}{11}\) 8/\(\left(-\dfrac{1}{3}\right).\left(-\dfrac{15}{19}\right).\dfrac{38}{45}\)
4/\(\left(-\dfrac{5}{11}\right).\dfrac{7}{15}.\dfrac{11}{-5}.\left(-30\right)\) 9/\(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+......+\dfrac{1}{19.20}\)
5/\(\left(-\dfrac{5}{9}\right).\dfrac{3}{11}+\left(-\dfrac{13}{18}\right).\dfrac{3}{11}\) 10/\(\dfrac{1}{9.10}-\dfrac{1}{8.9}-\dfrac{1}{7.8}-......-\dfrac{1}{2.3}-\dfrac{1}{1.2}\)
Tính
a, A = \(\dfrac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
b, B = \(\left(\dfrac{3}{7}.\dfrac{4}{15}+\dfrac{1}{3}.9^{15}\right).\dfrac{1}{3}.\dfrac{6^8}{12^4}\)
c, C = \(\dfrac{10^4.81-16.15^2}{4^4.675}\)
Thuc hien phep tinh:
a/ \(\dfrac{5}{15}\)+ \(\dfrac{14}{15}\) -\(\dfrac{12}{9}\)+ \(\dfrac{2}{7}\)+\(\dfrac{11}{25}\) d/ (\(9\dfrac{3}{4}\):5.2+3.4.\(2\dfrac{7}{34}\)) :(\(-1\dfrac{9}{16}\))
e/ \(\dfrac{2^8.9^2}{6^4.8^2}\)
b/ 4.(\(-\dfrac{1}{2}\))^3+\(\dfrac{1}{2}\)
c/ \(\dfrac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
\(\dfrac{2^{15}.9^4}{6^6.8^3}\)