Thuc hien phep tinh:
a/ \(\dfrac{5}{15}\)+ \(\dfrac{14}{15}\) -\(\dfrac{12}{9}\)+ \(\dfrac{2}{7}\)+\(\dfrac{11}{25}\) d/ (\(9\dfrac{3}{4}\):5.2+3.4.\(2\dfrac{7}{34}\)) :(\(-1\dfrac{9}{16}\))
e/ \(\dfrac{2^8.9^2}{6^4.8^2}\)
b/ 4.(\(-\dfrac{1}{2}\))^3+\(\dfrac{1}{2}\)
c/ \(\dfrac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
a: \(=\left(\dfrac{5}{15}-\dfrac{12}{9}\right)+\left(\dfrac{14}{15}+\dfrac{11}{25}\right)+\dfrac{2}{7}\)
\(=\left(\dfrac{1}{3}-\dfrac{4}{3}\right)+\dfrac{70+33}{75}+\dfrac{2}{7}\)
\(=-1+\dfrac{2}{7}+\dfrac{103}{75}=\dfrac{-5}{7}+\dfrac{103}{75}=\dfrac{346}{525}\)
b: \(4\cdot\left(-\dfrac{1}{2}\right)^3+\dfrac{1}{2}\)
\(=4\cdot\dfrac{-1}{8}+\dfrac{1}{2}=\dfrac{-1}{2}+\dfrac{1}{2}=0\)
c: \(\dfrac{10^3+5\cdot10^2+5^3}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot8+5\cdot5^2\cdot2^2+5^3}{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^3}\)
\(=\dfrac{5^3\left(8+4+1\right)}{3^3\left(8+4+1\right)}=\dfrac{125}{27}\)
e: \(\dfrac{2^8\cdot9^2}{6^4\cdot8^2}=\dfrac{2^8\cdot3^4}{3^4\cdot2^4\cdot2^6}=\dfrac{1}{4}\)
