a, \(3^{-2}.3^4.3^x=3^7\)
\(\Rightarrow3^{-2+4+x}=3^7\)
\(\Rightarrow3^{2+x}=3^7\)
Vì \(3\ne\pm1;3\ne0\) nên \(2+x=7\Rightarrow x=5\)
b, \(2^{-1}.2^x+4.2^x=9.2^5\)
\(\Rightarrow2^x\left(2^{-1}+4\right)=288\)
\(\Rightarrow2^x.4,5=288\Rightarrow2^x=64=2^6\)
Vì \(2\ne\pm1;2\ne0\) nên \(x=6\)
Chúc bạn học tốt!!!