\(\Leftrightarrow2018x^2-2018x+2019x-2019=0\\ \Leftrightarrow2018x\left(x-1\right)+2019\left(x-1\right)=0\\ \Leftrightarrow\left(2018x+2019\right)\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\2018x=-2019\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{2019}{2018}\end{matrix}\right.\)
Tìm x biết:
a, x^3 - 16x = 0
b, ( x -1 ) ( x + 2 ) - x - 2 = 0
c, 2 ( x +3 ) - x ( x + 3 ) = 0
Tìm x,biết:
a) x+5x^2=0
b)x+1=(x+1)^2
c)x^3+x=0
d)4x^2-4x=-1
e) 8x^3+12x^2+6x+1=0
f)x^3+5x-6=0
g)2y^3-3y^2-5y=0
h)2x(x+5)-x^3-5x^2=0
Mn giúp mk vs nha.
tìm x
a) x^2 - x = x - 1
b) (x^2 - 36) - (x+6) = 0
c) (2x-1)^2 - (4x^2 - 1)= 0
d) x^2(x^2 - 4) - (x^2 - 4 ) = 0
bài 4 : tìm x biết
a,4x2-49=0
b,x2+36=12x
c,\(\dfrac{1}{16}x^2\)-x+4=0
d,x3-3\(\sqrt{3x^2}\)+9x-3\(\sqrt{3}\)=0
e,(x-2)2-16=0
f,x2-5x-14=0
g,8x(x-3)+x-3=0
Tìm x a) x^2- 2x+1=0 b)x^2 - 9=0
tìm x biết
a. x (x+7)=0
b. x bình + 6x + 9
c. x mũ 3 -49x = 0
e x bình - 81 = 0
tìm x
a)(x+6)^2-x(x+9)=0
b)6x(2x+5)-(3x+4)(4x-3)=9
c)2x(8x+3)-(4x+1)=13
d)(x-4)^2-x(x+4)=0
e)(x-2)^2-(2x+3)(x-2)=0tìm x
x^2(x+1)+2x(x+1)=0
4/9-25x^2=0
tìm x biết
a) \(6x^3+x^2+x+1=0\)
b)\(5x+20-x^2-4x=0\)
c)\(x\left(2x-7\right)-4x+14=0\)
d) \(\left(2x-3\right)^2-\left(x+5\right)^2=0\)
