a. \(\dfrac{3}{4}-\left|2x+1\right|=\dfrac{7}{8}\)
=> \(\left|2x+1\right|=\dfrac{3}{4}-\dfrac{7}{8}\)
=> \(\left|2x+1\right|=\dfrac{-1}{8}\)
=> \(\left\{{}\begin{matrix}2x+1=\dfrac{-1}{8}\\2x+1=\dfrac{1}{8}\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=\dfrac{-9}{16}\\x=\dfrac{-7}{16}\end{matrix}\right.\)
#Yiin
b. \(2.\left|2x-3\right|=\dfrac{1}{2}\)
=> \(\left|2x-3\right|=\dfrac{1}{4}\)
=> \(\left\{{}\begin{matrix}2x-3=\dfrac{1}{4}\\2x-3=\dfrac{-1}{4}\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=\dfrac{13}{8}\\x=\dfrac{11}{8}\end{matrix}\right.\)
c: =>3|2x-5|=7,5+4,5=12
=>|2x-5|=4
=>2x-5=4 hoặc 2x-5=-4
=>2x=9 hoặc 2x=1
=>x=9/2 hoặc x=1/2
d: =>|x+4/15|=-2,15+3,75=1,6
=>x+4/15=8/5 hoặc x+4/15=-8/5
=>x=4/3 hoặc x=-28/15