Question

 19 { \left(2+3+4-5+6-7 \right) }^{  { 2  }^{ 2  }    }  -9 \left( 7x-2  \right)   =  0 

Answer 1

\( 19 { \left(2+3+4-5+6-7 \right) }^{ { 2 }^{ 2 } } -9 \left( 7x-2 \right) = 0 \)

\(\Rightarrow19\cdot\left(2+3+4+5+6-7\right)^4-9\left(7x-2\right)=0\)

\(\Rightarrow19\cdot\left(5+9-1\right)^4-9\left(7x-2\right)=0\)

\(\Rightarrow19\cdot13^4-9\left(7x-2\right)=0\)

\(\Rightarrow19\cdot28561-9\left(7x-2\right)=0\)

\(\Rightarrow542659-9\left(7x-2\right)=0\)

\(\Rightarrow9\left(7x-2\right)=542659\)

\(\Rightarrow7x-2=542659:9\)

\(\Rightarrow7x=\dfrac{542659}{9}+2\)

\(\Rightarrow7x=\dfrac{542677}{9}\)

\(\Rightarrow x=\dfrac{542677}{9}:7\)

\(\Rightarrow x=\dfrac{542677}{63}\)