Ta có : \(cos^2\alpha+sin^2\alpha=1\Rightarrow sin\alpha=\sqrt{1-cos^2\alpha}=\dfrac{\sqrt{3}}{2}\)
\(\Rightarrow\left\{{}\begin{matrix}tan\alpha=\dfrac{sin\alpha}{cos\alpha}=\sqrt{3}\\cot\alpha=\dfrac{cos\alpha}{sin\alpha}=\dfrac{1}{\sqrt{3}}\end{matrix}\right.\)