Sửa đề: \(16\left(x-1\right)^2-9\left(2x+1\right)^2=0\)
=>\(\left[4\left(x-1\right)\right]^2-\left[3\left(2x+1\right)\right]^2=0\)
=>\(\left(4x-4\right)^2-\left(6x+3\right)^2=0\)
=>\(\left(4x-4-6x-3\right)\left(4x-4+6x+3\right)=0\)
=>\(\left(-2x-7\right)\left(10x-1\right)=0\)
=>\(\left(2x+7\right)\left(10x-1\right)=0\)
=>\(\left[{}\begin{matrix}2x+7=0\\10x-1=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}2x=-7\\10x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{7}{2}\\x=\dfrac{1}{10}\end{matrix}\right.\)
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