\(\frac{1}{101.103}+\frac{1}{103.105}+...+\frac{1}{201.203}\)
=\(\frac{1}{1}.\left(\frac{1}{101}-\frac{1}{103}+...+\frac{1}{201}-\frac{1}{203}\right)\)
=\(\frac{1}{1}.\left(\frac{1}{101}-\frac{1}{203}\right)\)
=\(\frac{1}{1}.\frac{102}{20503}\)
= \(\frac{102}{20503}\)