(x - \(\frac{1}{2}\)) (2x - 3) = 0
TH1:
x - \(\frac{1}{2}\) = 0
⇒x = -\(\frac{1}{2}\)
TH2:
2x - 3 = 0
⇒x = \(\frac{3}{2}\)
VẬY x = {\(\frac{3}{2}\); -\(\frac{1}{2}\)}
NHớ tick và theo dõi mik nhá!
1. Tìm x:
c) 2- \(\frac{1}{3}\) / x-1/ = 5
e) /\(\frac{3}{5}\)/= /x-1/ = /\(\frac{-2}{5}\)/
(Mơn trc)
Bài 1:Tìm x thuộc Q a,|x + 3/5| - |x - 7/3 |=0
b,2.|3x-1/2| - 3.|x-1/2|=0
c,3.|1/2x - 1| - 5.|3/2x + 1|=0
Tìm x biết :
b) |x - 1| + 3x = 1
c) |2x - 1 = |2x + 3|
d) |x| + |x +2| = 0
e) \(\left|x.\left(x^2-\dfrac{5}{4}\right)\right|=x\)
Tìm x biết
a) |x(x-1)|+|(x+1)(x+5)|=0
b) |x^2-2x|+|(x+1)(x-2)|=0
Tìm x, biết:
a) |2x+5| - |x-1| = 0
b) |x+5| - 2|x+1| = 0
Tìm x biết :|x-2|+|3-2x|=2x+1
Tìm x:
a) |-3x + 4| + |x - 7| - x + 5 = 0
b) |-x+5| + |2x - 3| - |4x+7| = 0
c) |-x + 2| - |2x+4| - |x+3| - 2x + 1 = 0
~Pleaseee helppp meeeee!!!!
Tìm x, biết:
a) |-2x + 3| - 4 + x = 0
b) |\(\frac{1}{2}\)x + 2| - x + 5 = 0
Bài 4 : Tìm x,y biết :
a)\(3\dfrac{1}{4}-\dfrac{1}{4}\left|x-0,25\right|=\dfrac{1}{4}\)
b)\(\left|x-3\right|=-4\)
c)\(\left|x-\dfrac{1}{2}\right|+1=0\)
d)\(\left|x-\dfrac{1}{5}\right|=\left|\dfrac{3}{4}-2x\right|\)
e)\(\left|x+2\right|3=0\)
f)\(\left|2x-1\right|-\left|x+2\right|=0\)
g)\(\left|x+2\right|+\left|y-1\right|=0\)
h)\(\left|2x\right|+\left|y+\dfrac{1}{4}\right|=0\)
