a: \(A=\left(100^2-1\right)\left(100^4+100^2+1\right)=100^6-1\)
b: \(B=\left(\dfrac{1}{5}a-b\right)\left(\dfrac{1}{25}a^2+\dfrac{1}{5}ab+b^2\right)=\left(\dfrac{1}{5}a\right)^3-b^3=\dfrac{1}{125}a^3-b^3\)
c: \(C=\left(2+a\right)\left(4-2a+a^2\right)\left(2-a\right)\left(4+2a+a^2\right)\)
\(=\left(8+a^3\right)\left(8-a^3\right)=64-a^6\)