Question

1. Phân tích nhân tử

a) x\(^3\) - 27 + 2x\(^2\) - 6x

b) x\(^3\) + 2x\(^2\)y +xy\(^2\) - 16x

Answer 1

a)\(x^3-27+2x^2-6x=\left(x-3\right)\left(x^2+3x+9\right)+2x\left(x-3\right)=\left(x-3\right)\left(x^2+3x+9+2x\right)=\left(x-3\right)\left(x^2+5x+9\right)\)

Answer 2

b)Mình làm ra rồi nè :)) \(x^3+2x^2y+xy^2-16x=x\left(x^2+2xy+y^2-16\right)=x\left[\left(x+y\right)^2-4^2\right]=x\left(x+y-4\right)\left(x+y+4\right)\)

Answer 3

a) x³ - 27 + 2x² - 6x = (x - 3)(x² + 3x +9) + 2x( x - 3) = (x - 3)( x² + 3x +9 + 2x )

=(x-3)(x² +5x +9)

b) x³ +2x²y+xy²-16x = x(x² +2xy +y² -16 )= x[(x+y)² -16]=x(x+y+4)(x+y-4)

Answer 4

câu b) có sai đề ko bạn ?