\(\left|0,5x-2\right|-\left|x+\dfrac{2}{3}\right|=0\\ \Rightarrow\left|0,5x-2\right|=\left|x+\dfrac{2}{3}\right|\\ \Rightarrow\left[{}\begin{matrix}0,5x-2=x+\dfrac{2}{3}\\0,5x-2=-x-\dfrac{2}{3}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{16}{3}\\x=\dfrac{8}{9}\end{matrix}\right.\)
Tìm x biết
a. (0.5x-3/7):1/2=1 1/7
b. Đối 2-3 x -5=-1
c. (1/5-3/2x) tất cả mũ 2=9/4
Bài 1:Tìm x thuộc Q a,|x + 3/5| - |x - 7/3 |=0
b,2.|3x-1/2| - 3.|x-1/2|=0
c,3.|1/2x - 1| - 5.|3/2x + 1|=0
Tìm x:
a, -4/9 - 5/9 : x = 1/18
b, |x| = 1/2
c, x. ( x - 1/3 ) = 0
d, ( x - 2 ).( x + 3 ) < 0
e, ( x - 2 ).( x + 3 ) > 0
| 2 x - 3 | - | 3 x + 2 | = 0
tìm x. y
1)/x-3/-5+3x=0
2)\(\left(x-3\right)^2+2\left(y-3\right)^2=0\)
Tìm x bt
|1/2-x|+|1/5-y|+|1/3-z|<=0
|x^3-2x^2|+|x-2|<=0 giúp mik nha , cảm ơn !!
Tìm x khi:
(1/2.x -3) . (2/3.x + 1/2) = 0
Bài 1 :tìm x:
a)[x+1/2]=3
b)[2x-1]=-4
c)[3x-1]=0
d)[2-x].[3+x]=0
Tìm \(x\)\(\in\)\(Q\):
\(a\)\()\) \(|0,5.x-2|-|x+\dfrac{2}{3}|=0\)
\(b)\) \(2x-|x+1|=\dfrac{-1}{2}\)
