\(\left(12x-5\right)\left(4x-1\right)-\left(3x-7\right)\left(1+16x\right)=81\\ 48x^2-12x-20x+5-\left(3x+48x^2-7-112x\right)=81\\48x^2-12x-20x+5-3x-48x^2+7+112x=8\\ \left(48x^2-48x^2\right)+\left(-12x-20x-3x+112x\right)+\left(5+7\right)=81\\ 77x+12=81\\ 77x=81-12=69\\ x=\dfrac{69}{77} \)
Vậy \(x=\dfrac{69}{77}\)




