ĐKXĐ: \(y\ne-2\)
Đặt \(\left\{{}\begin{matrix}x-1=u\\\dfrac{1}{y+2}=v\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}2u+3v=12\\3u+v=-3\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}2u+3v=12\\9u+3v=-9\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2u+3v=12\\7u=-21\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}-3.2+3v=12\\u=-3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}v=6\\u=-3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x-1=-3\\\dfrac{1}{y+2}=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=-2\\y=-\dfrac{11}{6}\end{matrix}\right.\)
