Question

giải HPT

\(\left\{{}\begin{matrix}\dfrac{4}{x}+\dfrac{3}{y}=-1\\\dfrac{3}{x}-\dfrac{2}{y}=5\end{matrix}\right.\)

Answer 1

Lời giải:

Ta có: \(\left\{\begin{matrix} \frac{4}{x}+\frac{3}{y}=-1\\ \frac{3}{x}-\frac{2}{y}=5\end{matrix}\right.\Leftrightarrow \left\{\begin{matrix} \frac{8}{x}+\frac{6}{y}=-2(1)\\ \frac{9}{x}-\frac{6}{y}=15(2)\end{matrix}\right.\)

Lấy \((1)+(2)\Rightarrow \frac{17}{x}=-2+15=13\)

\(\Rightarrow x=\frac{17}{13}\)

\(\frac{2}{y}=\frac{3}{x}-5=\frac{39}{17}-5=\frac{-46}{17}\)

\(\Rightarrow y=\frac{-17}{23}\)

Vậy......