\(b)3x(x+5)-2x-10=0\)
\(<=>3x(x+5)-2(x+5)=0\)
\(<=>(x+5)(3x-2)=0\)
\(<=>\) \(\left[{}\begin{matrix}x+5=0\\3x-2=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=-5\\x=\dfrac{2}{3}\end{matrix}\right.\)
a: =>x^2+8x+16-x^2+2x-3x+6=-13
=>7x+22=-13
=>7x=-35
=>x=-5
b: =>(x+5)(3x-2)=0
=>x=2/3 hoặc x=-5
a.
\(\Leftrightarrow x^2+8x+16-\left(x^2+x-6\right)=-13\)
\(\Leftrightarrow x^2+8x+16-x^2-x+6=-13\)
\(\Leftrightarrow7x=-35\)
\(\Leftrightarrow x=-5\)
b.
\(3x\left(x+5\right)-2x-10=0\)
\(\Leftrightarrow3x\left(x+5\right)-2\left(x+5\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+5=0\\3x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{2}{3}\end{matrix}\right.\)