Question

Answer 1

a: =>x=1

b: =>16x2^x=2¹²

=>2^x=2⁸

hay x=8

c: =>3^x+2=27

=>x+2=3

hay x=1

Answer 2

\(a,=>x=1\)

\(b,=>16x2^x=2^{12}\)

\(=>2^x=2^8\)

Hay x=8

\(c,=>3^{x+2}=27=>x+2=3\)

Hay x=1