ĐKXĐ: \(x\ne-5\)
Ta có: \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7\left(x-1\right)=6\left(x+5\right)\)
\(\Leftrightarrow7x-7=6x+30\)
\(\Leftrightarrow7x-7-6x-30=0\)
\(\Leftrightarrow x-37=0\)
hay x=37(nhận)
Vậy: x=37
ĐKXĐ: \(x\ne-5\)
Ta có: \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7\left(x-1\right)=6\left(x+5\right)\)
\(\Leftrightarrow7x-7=6x+30\)
\(\Leftrightarrow7x-7-6x-30=0\)
\(\Leftrightarrow x-37=0\)
hay x=37(nhận)
Vậy: x=37
1,Tìm x,biết
a,\(\left(-1\dfrac{3}{5}+x\right)\div\dfrac{12}{13}=2\dfrac{1}{6}\)
b,\(\dfrac{-4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}\div\left(-1\dfrac{2}{3}\right)\)
Bài 17: Tìm x, biết
a) \(\left(\dfrac{1}{7}x-\dfrac{2}{7}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)=0\)
b) \(\dfrac{1}{6}x+\dfrac{1}{10}x-\dfrac{4}{15}x+1=0\)
Giúp mk vs, ai nhanh mk sẽ tick
\(\dfrac{5^5}{5^x}=5^{18}\)
\(\dfrac{x-7}{6}=\dfrac{3}{2\left(x-7\right)}\)
bài 1 tính
a/ \(\left|1\dfrac{1}{2}-2\dfrac{1}{3}\right|^2+\left|1-\dfrac{5}{4}\right|\)
b/\(\left|\left(-1\right)^{100}-2\dfrac{1}{3}\right|+\dfrac{5}{6}\)
c/\(\left|\left(\dfrac{2}{3}\right)^{-1}-\dfrac{7}{4}\right|-\dfrac{7}{4}\)
d/ \(\left|x-5\right|+\left|x-8\right|\) với 5 \< x>/
\(\left(\dfrac{-5}{8}\right)-x\div3\dfrac{5}{6}+7\dfrac{3}{4}=-2\)
Tìm x,y biết
a.\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+1}=0\)
b.\(\dfrac{5x-1}{3}=\dfrac{7y-6}{5}=\dfrac{5x+7y-7}{4x}\)
c.\(\left|x+5\right|+\left(3y-4\right)^{2017}=0\)
Tìm x biết:
1) \(\dfrac{x+1}{2}+\dfrac{x+1}{3}+\dfrac{x+1}{4}=\dfrac{x+1}{5}+\dfrac{x+1}{6}\)
2) \(\dfrac{x+1}{2009}+\dfrac{x+2}{2008}+\dfrac{x+3}{2007}=\dfrac{x+10}{2000}+\dfrac{x+11}{1999}+\dfrac{x+12}{1998}\)
Tìm x :
a)\(\dfrac{x-1}{x=5}=\dfrac{6}{7}\)
b)\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)
Tìm x; y biết:
a) \(\dfrac{x}{4}\)= \(\dfrac{y}{3}\)=\(\dfrac{2}{9}\) và x - 3y + 42 = 62
b) \(\dfrac{x}{y}\)=\(\dfrac{7}{9}\) và \(\dfrac{y}{z}\)= \(\dfrac{7}{3}\) và x - y + z = -15
c)\(\dfrac{x}{y}\)=\(\dfrac{7}{20}\); \(\dfrac{y}{z}\)=\(\dfrac{5}{8}\) và 2x + 5y - 2z =100
d) 5x = 8y = 20 và x-y-z = 3
e) \(\dfrac{6}{11}\) . x =\(\dfrac{2}{2}\). y =\(\dfrac{18}{5}\). z và (-x) +y + 2 = -120
f ) \(\dfrac{x}{12}\)=\(\dfrac{y}{9}\)=\(\dfrac{2}{5}\) và x . y . z =20