Question

Answer 1

a: =>(x-1)(x+1)=0

=>x=1 hoặc x=-1

b: \(\Leftrightarrow\left(x+2\right)\left(x-1\right)=0\)

=>x=-2 hoặc x=1

c: \(\Leftrightarrow x^2\left(x-1\right)+x-1=0\)

=>x-1=0

hay x=1

d: \(\Leftrightarrow x^2\left(2x-1\right)+\left(2x-1\right)\left(2x+1\right)=0\)

=>(2x-1)(x+1)²=0

=>x=1/2 hoặc x=-1