\(a,2\left(x-3\right)< x+7\\ \Leftrightarrow2x-6-x-7< 0\\ \Leftrightarrow x-13< 0\\ \Leftrightarrow x< 13\\ b,x-\dfrac{x+2}{6}\ge\dfrac{x-1}{3}+5+\dfrac{2x}{5}\\ \Leftrightarrow30x-5\left(x+2\right)\ge10\left(x-1\right)+30.5+6.2x\\ \Leftrightarrow30x-5x-10\ge10x-10+150+12x\\ \Leftrightarrow30x-5x-10-10x+10-150-12x\ge0\\ \Leftrightarrow3x-150\ge0\\ \Leftrightarrow3x\ge150\\ \Leftrightarrow x\ge50\)
`a)`\(2\left(x-3\right)< x+7\)
\(\Leftrightarrow2x-6< x+7\)
\(\Leftrightarrow x< 13\)
Vậy \(S=\left\{x|x< 13\right\}\)
`b)`\(x-\dfrac{x+2}{6}\ge\dfrac{x-1}{3}+5+\dfrac{2x}{5}\)
\(\Leftrightarrow\dfrac{30x-5x-10}{30}\ge\dfrac{10x-10+150+12x}{30}\)
\(\Leftrightarrow25x-10\ge22x+140\)
\(\Leftrightarrow3x\ge150\)
\(\Leftrightarrow x\ge50\)
Vậy \(S=\left\{x|x\ge50\right\}\)
giải thích giùm mình với