Question

Answer 1

a: ĐKXĐ: x+1<>0

hay x<>-1

b: ĐKXĐ: \(\left\{{}\begin{matrix}1-x>=0\\2-x>=0\end{matrix}\right.\Leftrightarrow x< =1\)

c:ĐKXĐ: x-3>0

hay x>3

Answer 2

\(a,ĐKXĐ:x+1< >0\)

\(Hayx< >-1\)

\(b,ĐKXĐ:\left\{{}\begin{matrix}1-x>=0\\2-x>=0\end{matrix}\right.\Leftrightarrow x< =1\)

\(c,ĐKXĐ:X-3>0\)

-> Hay \(x>3\)