2:
a: \(P=\dfrac{x+3\sqrt{x}+2+2x-4\sqrt{x}-2-5\sqrt{x}}{x-4}\)
\(=\dfrac{3x-6\sqrt{x}}{x-4}=\dfrac{3\sqrt{x}}{\sqrt{x}+2}\)
b: Để P=2 thì \(3\sqrt{x}=2\sqrt{x}+4\)
hay x=16
c: Thay \(x=9+4\sqrt{5}\) vào P, ta được:
\(P=\dfrac{3\left(\sqrt{5}+2\right)}{\sqrt{5}+2+2}=\dfrac{3\sqrt{5}+6}{\sqrt{5}+4}=\dfrac{9+6\sqrt{5}}{11}\)