Question

Answer 1

\(n_S=\dfrac{3,2}{32}=0,1mol\)

\(S+O_2\rightarrow\left(t^o\right)SO_2\)

0,1 0,1             0,1   ( mol )

Tỉ lệ : 1:1:1

\(V_{O_2}=V_{SO_2}=0,1.22,4=2,24l\)

Answer 2

\(n_S=\dfrac{3,2}{32}=0,1\left(mol\right)\\ PTHH:S+O_2\underrightarrow{t^o}SO_2\\ Mol:0,1\rightarrow0,1\rightarrow0,1\\ V_{SO_2}=V_{O_2}=0,1.22,4=2,24\left(l\right)\)