a: \(\Leftrightarrow2\left(2x+1\right)+x=7\left(2x+1\right)\)
=>4x+2+x=14x+7
=>5x+2=14x+7
=>14x+7=5x+2
=>9x=-5
hay x=-5/9(nhận)
b: \(\Leftrightarrow5+\left(-2x+1\right)\left(3x+2\right)=0\)
\(\Leftrightarrow-6x^2-4x+3x+2+5=0\)
\(\Leftrightarrow-6x^2-x+7=0\)
\(\Leftrightarrow6x^2+x-7=0\)
=>(6x+7)(x-1)=0
=>x=-7/6(nhận) hoặc x=1(nhận)
c: \(\dfrac{x}{2\left(x-3\right)}+\dfrac{x}{2\left(x+1\right)}=\dfrac{2x}{\left(x-3\right)\left(x+1\right)}\)
\(\Leftrightarrow x^2+x+x^2-3x=4x\)
\(\Leftrightarrow x^2-2x-4x=0\)
=>x(x-6)=0
=>x=0 hoặc x=6
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