Bài 1:
\(a,=\dfrac{4x-8}{x-2}=\dfrac{4\left(x-2\right)}{x-2}=4\\ c,=\dfrac{3x+1-2x}{x\left(x+1\right)}=\dfrac{x+1}{x\left(x+1\right)}=\dfrac{1}{x}\\ e,=\dfrac{2x-3+2x^2+2x-3x+3}{\left(x-1\right)\left(x+1\right)}=\dfrac{2x^2+x}{\left(x-1\right)\left(x+1\right)}\\ b,=\dfrac{x-13+x+3}{x-5}=\dfrac{2\left(x-5\right)}{x-5}=2\\ d,=\dfrac{x+4+x-4-3x}{x\left(x-4\right)}=\dfrac{-x}{x\left(x-4\right)}=\dfrac{1}{4-x}\\ f,=\dfrac{x+8-16+2x-16}{\left(x-8\right)\left(x+8\right)}=\dfrac{3x-24}{\left(x-8\right)\left(x+8\right)}=\dfrac{3\left(x-8\right)}{\left(x-8\right)\left(x+8\right)}=\dfrac{3}{x+8}\)
Bài 1:
b: \(=\dfrac{x-13+x+3}{x-5}=2\)
f: \(=\dfrac{x+8-16+2x-16}{\left(x-8\right)\left(x+8\right)}=\dfrac{3x-24}{\left(x-8\right)\left(x+8\right)}=\dfrac{3}{x+8}\)
