\(a,c,\text{Làm rồi}\\ b,=\dfrac{2x+4-2x+4}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{\left(x+2\right)^2}{8}=\dfrac{x+2}{x-2}\\ d,=\dfrac{5x^2+26xy+5y^2+5x^2-26xy+5y^2}{x\left(x-5y\right)\left(x+5y\right)}\cdot\dfrac{\left(x-5y\right)\left(x+5y\right)}{x^2+y^2}\\ =\dfrac{10\left(x^2+y^2\right)}{x\left(x^2+y^2\right)}=\dfrac{10}{x}\)





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