Question

Answer 1

\(a,=\dfrac{5xy-4y+3xy+4y}{2x^2y^3}=\dfrac{8xy}{2x^2y^3}=\dfrac{4}{xy^2}\\ c,=\dfrac{3x-x+6}{2x\left(x+3\right)}=\dfrac{2\left(x+3\right)}{2x\left(x+3\right)}=\dfrac{1}{x}\\ e,=\dfrac{y-x}{xy\left(y-x\right)}=\dfrac{1}{xy}\\ g,=\dfrac{x^2-9-x^2+9}{x\left(x-3\right)}=0\\ i,A=\dfrac{1+x+1-x}{1-x^2}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}\\ A=\dfrac{2+2x^2+2-2x^2}{1-x^4}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}\\ A=\dfrac{4+4x^4+4-4x^4}{1-x^8}+\dfrac{8}{1+x^8}\\ A=\dfrac{8+8x^8+8-8x^8}{1-x^{16}}=\dfrac{16}{1-x^{16}}\)